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abdullahQA

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  • iDevice
    iPhone X
  • iOS Version
    11.4B3
  • Jailbroken
    Yes
  • Rooted
    No

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  1. login = "http://xxx.com/login.php" local user = gg.prompt({'Username', 'Password'}, {}, {[1]='text',[2]='text'} ) if user[1] == '' or user[2] == '' then gg.alert ("Username Or password is Wrong") else data = assert(load(gg.makeRequest(login ,nil,'username='..user[1]..'&password='..user[2]).content)) return data() end if data == '0' then print ("Login failed, please try again.") os.exit(); end i have create this could but the problem when i enter the username and password that login right and no issue but if i enter username or password wrong that not showing me print ("Login failed, please try again.") and i getting issue with its i don't now where is the issue could you help me.
  2. walls shot hack f32 or f64 869 or 711 or 55 search Number 2 change -4 or -1 or -10
  3. Bypass 1- 1.2F;1.8F:9::1 1.1F;1.4F:3::1 1.1D;1.4D:2::10 5001;1.1;1F::10 = 100 Bypass 2 1.2F;1.8F:9::1 1.1F;1.4F:3::1 1.1D;1.4D:2::10 5001;1.1;1F::10 = 800 Good Luck IDA 0.7
  4. Hello, i have created script ,lua and i would like linked this with website php or html checking for example the code is XXX if menu1 == 1 then A() end if menu1 == 2 then B() end if menu1 == 3 then C() end if menu1 == 4 then D() end if menu1 == 5 then Exit() end XXX and to start the code should be first checking with my webite like "http://xxx.com/xx.php" if i have add source "1" the script is open if i have change it my website to "0" script not open and end could you help me
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