Help/Support Found function, now what?

[Joka 3.8k N/A N/A]

Hello,

 

So I've managed to find a function (I think so) and it looks like this:

I think I have to change the LDR instruction to something and leave the BX LR but what do I change it to?

If someone could help me understand what I have to do from this point, I'd appreciate it!

 

Thank you.

[Ted2 39.2k Donor]

LDR R0, [R7]

BX LR.

 

this will load 803milion into R0 (the main value)

 

i think MOV R0, R7 would work too

Updated July 5, 2017 by Ted2

[Joka 3.8k N/A N/A]

Just now, Ted2 said:

LDR R0, [R7]

BX LR.

 

this will load 803milion into R0

Awesome. Lemme test.

2 minutes ago, Ted2 said:

LDR R0, [R7]

BX LR.

 

this will load 803milion into R0

What's the freeze instruction? The instruction that'll freeze the value?

[Ted2 39.2k Donor]

3 minutes ago, Joka said:

Awesome. Lemme test.

What's the freeze instruction? The instruction that'll freeze the value?

Not sure what you mean by freeze? Like it stays the same for ever? I think you have to use mov r0, r7 for that.. Not sure tho

[TheArmKing 60.4k Xiaomi A1 9.0.0 Pie]

5 minutes ago, Ted2 said:

LDR R0, [R7]

BX LR.

 

this will load 803milion into R0 (the main value)

 

i think MOV R0, R7 would work too

MOV and LDR go hand in hand ?

[Ted2 39.2k Donor]

4 minutes ago, TheArmKing said:

MOV and LDR go hand in hand ?

Yea, sometimes u can just change LDR to a MOV, artleast I've done it + tutorials say that it can be done too